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컴퓨터/Data Structure/Algorithm

[Programming Challenge] 1.6.6 Interpreter

1.6.6 Interpreter

PC/UVa IDs: 110106/10033, Popularity: B, Success rate: low Level: 2

A certain computer has ten registers and 1,000 words of RAM. Each register or

RAM location holds a three-digit integer between 0 and 999. Instructions are encoded

as three-digit integers and stored in RAM. The encodings are as follows:

100 means halt

2dn means set register d to n (between 0 and 9)

3dn means add n to register d

4dn means multiply register d by n

5ds means set register d to the value of register s

6ds means add the value of register s to register d

7ds means multiply register d by the value of register s

8da means set register d to the value in RAM whose address is in register a

9sa means set the value in RAM whose address is in register a to that of register s

0ds means goto the location in register d unless register s contains 0

All registers initially contain 000. The initial content of the RAM is read from standard

input. The first instruction to be executed is at RAM address 0. All results are

reduced modulo 1,000.


Input

The input begins with a single positive integer on a line by itself indicating the number

of cases, each described as below. This is followed by a blank line, and there will be a

blank line between each two consecutive inputs.

Each input case consists of up to 1,000 three-digit unsigned integers, representing the

contents of consecutive RAM locations starting at 0. Unspecified RAM locations are

initialized to 000.


Output

The output of each test case is a single integer: the number of instructions executed

up to and including the halt instruction. You may assume that the program does halt.

Separate the output of two consecutive cases by a blank line.


Sample Input

1

299

492

495

399

492

495

399

283

279

689

078

100

000

000

000


Sample Output

16